T19

Pomocí Taylorova vzorce vypočítejte přibližně taylor series sin x

\( \sqrt[3]{30} \) taylor cuberoot 30

series x^1/3 at x=27 order to 2

\( \sqrt[5]{250}, 3^5 = 243 \) series x^1/5 at x=243 order to 3

\( \sqrt[12]{4000} 2^12 = 4096 \) 4000^1/12 series x^1/12 at x=4096 order to 3

\( \sqrt{e} \) sqrt e

\( \sin 18 \)

\( \ln 1.2 \) taylor ln 1.2

\( \arctan 0.8 \)

\( \arcsin 0.45 \)

\( 1.1^{1.2} \) 1.1^1.2